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x^2+17x-1260=0
a = 1; b = 17; c = -1260;
Δ = b2-4ac
Δ = 172-4·1·(-1260)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-73}{2*1}=\frac{-90}{2} =-45 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+73}{2*1}=\frac{56}{2} =28 $
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